java - What is the difference between #.## and ##.## pattern in Decimal Format? -


In my program I #. ## I am using the pattern decimalfile as shown below: 

  decimalf df = new substitute ("###") ;   
 By accident I have an additional  #  shown below:  
  decimalf df = new decimal ("##. # # ");   
 but it does not affect my output. I have tried to use different combinations of input that there is no difference in the output  
 then "#. And ## # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # # ###########################  Edit:   
 If both are - Why is it the same in both cases?  
  Edit:   
  Sample Program:   
  import java.text.Dec ImalFormat; Public square tithe {public static zero main (string [] args) {double D1 [] = new double [] (100D, -100, -0.111111D, 2.555666D, 55555555555D, 0D}; decimalfile df1 = New Decimal False ("####); decimalfile df2 = new for the decimal number (" ## # # "); (double D: D1) {System.out.println (df1.format (d)); Println (df2.format (d));}}}   
  Output:   
  100 100 -1 -1 - 0.11 -0.11 2.56 2.56 55555555555 55555555555 0    
 
 
 imho,  decimalf  to fully formatted Expertise is  numbers> represntation  and to control the  number of points after a number .  
 Then  #  and  ##  before the decimal (. ) does not behave differently. Of course, if after decimals (. ) )  
 assuming 12.234 as an input number:  
 12.234 and 12.23 will mean / but 12.234 And there will be no meaning for 2.234. 
  
 The emphasis is placed on formats and values ​​as a decimal point:  
     
  •  
      SetInfine Digits (0);    
  •  
      setMaximumFractionDigits (2);    
  •  
      setRoundingMode

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