c - initializing a function externally -


I would like to return a function with a variable inside that I can initialize it inside the function that gives it Possible, or not? int get_char (char * c) {static circular_queue * cir; // It needs to be started in the function below if (circular_queue_empty (cir)) 0; Else * c = circular_queue_pop (cir); Return 1; } Int (* generate_get_char (circular_queue * cir)) (char * c) {// Circuit Return & amp; Do something to set get_char; }

I am passing the pointer together in an API which I do not control so I can not change the format of get_char ; It is being said that there is a better way to do this because I am quite sure that the above is not possible. (I will not use a static global, but all I can think of doing).

TY

Variables with static storage allocations are started at zero by default Are there. Therefore, the following statements are effectively equivalent. 

  Fixed circular_que * cir; // constant circular_queue * cir = 0 equals; // constant circular_queue * cir = NULL equals;   
 There is a work scope in the variable  cir , that is, this function can be accessed in  get_char . Therefore, the answer to your question  
 
 I would like to return a function with a variable inside that I can initialize it inside the function which it gives is possible, or is not it?    
 You do not need a global variable which is visible for both  get_char  and  generate_get_char  functions. Also, note that the name of a function indicates on the indicator. Therefore, the following are equivalent -  
  return and get_char; // get_char equal to return;

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