counting occurrence of consecutive elements in a list (python) -


given a list 

  a = ['g', 'd', 'r I want to count as GDR incident for example, so I will apply some functions. Returned  a.function ('g', 'd', 'r') and sent me  2  (since gdr was 2 times).  
 
 
 
 If they are the  only  string in the list, And its  count  method:  
  & gt; & Gt; & Gt; A = ['g', 'd', 'r', 'x', 's', 'g', 'd', 'r']> gt; & Gt; & Gt; For example, if you have a mix of strings and numbers, you can use the  map (str, a). And the method will still work before joining:  
  & gt; & Gt; & Gt; a = [1,13,4,2,1,13,4] & gt; & Gt; & Gt; ''. () () (), () () () () () (), () () () () (), 
 
  def count_pattern (lst, * pattern): return '' .join (L) .count (''. Join (pattern))   
 and will be able to call it:  count_pattern (a, 'g', 'd', ' R ')  or  count_pattern (a,' gdr ')  or even  count_pattern (a,' gd ',' r ') .

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