php - "mysqli_fetch_array() expects parameter 1 to be mysqli_result, string given" error - 


  & lt;; doctype html & gt; & LT; html & gt; & Lt; शीर्ष & gt; & Lt; title & gt; सभी & lt; / title & gt; & Lt; / head & gt; & LT; बॉडी & gt; & lt;? php शामिल ("connection.php"); $ Result = mysqli_query ($ con, "student_data से चुनें") या मर ('क्वेरी विफल'); जबकि ($ पंक्ति = mysqli_fetch_array ('$ परिणाम')) {गूंज $ पंक्ति ['नाम']; प्रति पंक्ति गूंज ['fname']; प्रति पंक्ति गूंज ['sid']; प्रति पंक्ति गूंज ['ईमेल']; गूंज "& lt; br & gt;"; }? & Gt; & Lt; / body & gt; & Lt; / html & gt;   
 यह मुझे डेटाबेस में हर डाटा को प्रिंट करने के लिए लगता है। लेकिन मुझे निम्नलिखित त्रुटि मिलती है मुझसे कहां गलती हो रही है? यहां छवि विवरण दर्ज करें   
 
 
 एपॉस्ट्रॉफ़ को  $ परिणाम  के आस-पास हटा दें। यह  mysqli_fetch_array ('$ परिणाम')  होना चाहिए  mysqli_fetch_array ($ परिणाम)   
 अंतर ध्यान दें:  
   mysqli_query     $ परिणाम    div>

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