Why does Python not have an 'is even' method for integers and what should I do about it? -


There is no 'is_even' method or nothing for integer in Python.

For example: 

  if with integer_value%, 2 == 0: do something   
 It is not clear what to really do.  
 While it is more understandable immediately:  
  if_even (integer_value): # something   
 this means That I need to write an AVIven function where I want it.  
  def is_even (integer): if integer% 2 == 0: return true: return wrong   
 What is a better option? What is the code itself that is readable and clearly intended, or is there comments everywhere?  
 To quote a recent blog entry which is rounding:  
 "Notice how much stronger this approach is compared to using comments, if you have arguments If you change, you put immediate pressure to change the variable name, it is not so with comments. I agree with DHH, the comment is dangerous and is caused by rot - it is better to write self-documentation code. > 
 Am I this multi   
 
 
 There is usually no problem in  local  functions - or using lambdas - and I usually do this when they make it more pronounced.  
 However, the  core  language of particular functions of this class is generally unnecessary , And to move the path of bloated core down to add to the global / underlying function (or even as a special type of method) Habit: Why not  is_prime  or  is_natural ?  
  def do_my_stuff (numbers): def is_even (i): return i % 2 == 0 # Usage is_even, where this return can be referenced above the map (numbers, is_even)

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