Convert all the elements in a file into a array in haskell -


I have a file that has a set of 200,000 words and I want to read the program data and store it in array. And make a new array with all 200,000 words.

I import the code 

  system.IO main = do handle and lt; - Openfile is written as "words.txt"   
 but giving error as type error on line 5  
 "ReadModa content & lt; - hGetContentsCon & lt; - Rows content putStrLn (show con) hClose handle   
 and the text file is a form  
  ABRIDGMENT ABRIDGMENTS ABRIIN ABRIN ABRINS ABRIS   
 and so on  
 What is the amendment  
  def readFile (): allwords = [] for the word in open  
 < Code>  
 ("Words.txt"): allwords.append (word.strip ()) return all words    
 
 
 can be  
  readFile "words.txt" & gt; & Gt; = Return   
 type  
  :: IO [string]   
 or you can write    getWordsFromFile :: string - & gt; IO [string] getWordsFromFile file = read file file & gt; = = Return   
 and  
 use  as  word = "word.txt" getStrLn $ "file is included" ++ (Length word list) ++ "word." Very constructive comments from @Sanityinc and @Sarah (thanks!): @Sanityinc:  "Other option:  fmap word $ readFile file  by & lt; $ & gt;   control.profit  " or  word & lt; $ & Gt; ReadFile file  / Em>  
 @ Sarah:  "When you see  foo>> = return bar bar  It can be changed with  fmap bar foo  because you are not actually using additional forces that come with  monad  and in most cases without any complex type There is more true in the future, where  applicable   monad  "    A super word of / html> Is c

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