php - Insert on duplicate key update didn't update, instead insert new value -


I have a table with 4 lines, 1 is the primary key with automatic increments, the line is check_id ..

What do I have to do Insert a new data if no data exists and updates data based on ID if it exists.

I'm already using it: 

 Checklist on duplicate key updates (check_pos, check_off, check_code) value ('$ name', '$ name ',' $ Code '), check_core =' $ name '  
 but enter only a new value  
 Instead, I have the code  check_id Tried > to the  unique key  and this is the same,  
 Is there anything wrong with my update query or my table?  
 This is my code:  
  & lt ;? php $ ew = mysql_query ("choose from pos_unit * where pos_unit_name '% director%'"); $ Line = mysql_num_rows ($ ew); While ($ eq = mysql_fetch_array ($ ew)) {$ pos = $ eq ['pos_unit_name']; $ Checklist = mysql_query ("select from checklist * where check_ok = '$ pos'"); $ Excheck = mysql_fetch_array ($ checklist); $ Poss = $ excheck ['check_pos']; ? & Gt; & Lt; Li & gt; & Lt; div class = "form_grid_12" & gt; & Lt; Label class = "field_title" id = "real" & gt; & Lt ;? Php echo $ eq ['pos_unit_name']; ? & Gt; & Lt; / Labels & gt; & Lt; Div class = "form_input" & gt; & Lt; Input type = "hidden" name = "id []" value = "& lt ;? php echo $ cost ['check_id'] ;;>" & Gt; & Lt; Input name = "condition []" class = "checkbox" type = "checkbox" & lt ;? Php if (echo = $ $ poss) echo "check = 'check'"; ? & Gt; Value = "& lt ;? php echo $ eq ['pos_unit_name'] ;? & gt;" Style = "opacity: 0;" & Gt; & Lt; / Div & gt; & Lt; / Div & gt; & Lt; / li & gt; & Lt ;? Php}? & Gt;   
 And this is php code.  
  Include 'config.php'; $ Code = $ _POST ['code']; $ Id = $ _POST ['id']; // $ dist = $ _POST ['selectdistarg']; $ Check = $ _POST ['status']; // $ input = $ _POST ['selectinp']; // $ eval = $ _POST ['selectval']; Value in '$ name', '$ name', '$ code in the checklist (check_poose, check_off, check_code) on {$ up = mysql_query (duplicate key), check the foreign currency ($ index = & gt; $) '); Enter (mysql_error ());}    
 
 Enter the search_check =' $ names' ") or die 
 The database is performing as expected.  
 Every time you get a new, autonombed value in  INSERT  you get a new record in  check_id  Because it's the  primary key  of the table And because you have not declared any other  UNIQUE INDEX  es, there is never a duplicate key status.  
 You want to receive behavior, to declare you Once you have done this, along with the additional  unique index  columns that make each row really unique, you delete  check_id  and the  primary of the table Key  to become  UNIQUE INDEX  The Awa can consider.

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