jquery - How To Get ASP.NET MVC Form To do same as button submit -


मेरे पास एक साधारण एएसपी.नेट एमवीसी फॉर्म है जिसके पास कोड निम्न है: 

  @ उपयोग (एचटीएमएल.बीजिनफॉर्म (रिक्त, रिक्त, फॉर्ममैथ.पस्ट, नया {action = "https://secure.authorize.net/gateway/transact.dll", आईडी = "रजिस्टर फॉर्मिड"}}) {@Html छिपे हुए (एक = & gt; a.RegisterUserInfoLoggedIn.AttendeesId) ...   
 मुझे एक JQuery AJAX कॉल मिल गया है और अगर JQuery सफल है, तो मैं अपना फॉर्म पोस्ट करने के लिए चाहता हूं आगे की प्रक्रिया के लिए एक्शन यूआरएल।  
 मेरा JQuery निम्न की तरह दिखता है, लेकिन जो मुझे पता नहीं है वह क्या है जो मेरी JQuery अजाक्स सफलता की घटना में डालता है, जैसे कि मैं वापस कार्रवाई यूआरएल पर पोस्ट करता हूं, पृष्ठ ठीक से जवाब देता है और मुझे अपना नया पृष्ठ दिखाता है  <पूर्व>  सफलता: फ़ंक्शन (डेटा) {यदि (दान राशि & gt; 0.00) {$ .post ("https://secure.authorize.net/gateway/transact.dll", {x_login: 'xxx', x_amount: 1 9। 9 9, x_description: 'नमूना लेनदेन', ...}, फ़ंक्शन (डेटाकैक्स) {this.submit ();});    
 
 
 आप अपने फ़ॉर्म को  का उपयोग कर सबमिट कर सकते हैं। सबमिट करें ()   <पूर्व>  सफलता: फ़ंक्शन (डेटा) {$ ('# registerformid')। सबमिट करें (); // यहीं। }

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