c - fprintf ignore ^M carriage returns -


I have such a set up my phopan, I tried both my FOPIN without "T" and "T" is. For some reason my fprintf ^ M is printing out what the carrier returns. How do I stop frpintf from doing this? I just want to use the character of normal new line 

  FILE * outputfp; The location is for +5 to .5 and terminator four * fname = calloc (strlen (argv [1]) + 5, size (fname [0])); Strapepie (FNA, AGRV [1]); Dome (fname, ".lst"); Outputfp = fopen (fname, "w"); // printf ("above error message \ n"); If (outputfp == NULL) {printf ("Error opening file. \"); Return 1; } Fprintf (outputfp, "hello \ n");   
  
 I am using Fedora and I am compiling it with GCC  
  Update:   
  if ((int) line [0] == 46) {// printf ("you have a duration \ n"); // printf ("% s", line); {// fprintf (outputfp, "% c", line [i]) for (i = 0; i & lt; 80; i ++); If (ISPrint (unsigned char) line [i]) || Operation ((unsigned char) line [i])) {printf ("% c", line [i]); // fprintf (outputfp, "\ nprint something \ n"); Fprintf (outputfp, "% c", line [i]); } // printf ("% c", line [i]); // printf ("% d% c", line [i], line [i]); } // fprintf (outputfp, "\ n"); // printf ("------------------------ \ n"); Memset (line, 0, 80); Comment_flag = 1; } // sscanf (line, "% s% s% x", label, moneymine, and start_address); // printf ("start_address% d \ n", start_address); Printf ("% x% s% s% s% s% x \ n", start_address, label, mneumonic, operand, start_address); Fprintf (outputfp, "% x% s% s% s% x \ n", start_address, label, manual, operation, start_address);   
 It really looks like this is a line that is not liked. Before I print a new line character, I want to cycle through my entire array.  
  fprintf (outputfp, "% c", line [i]);   
  Update:   
  Four lines [80] = {0}; While (fgets (line, 80, input)! = NULL)    
 
 
  "T" is the default  if you want binary mode then open from  "wb" .  
 A text stream (default) can perform different conversions between the disk file and your C program; A binary stream means 1-1 letter mapping (though it is fully implemented-defined).  
  Update:  Since you are working in Linux, there is probably no problem in text or binary mode.  
 Depending on your output screenshot, it seems that you have actually typed a file  \ r  in the first line is not one if you actually show that code Which will produce that output, it would be helpful that you are reading rows from that file in which the  \ r \ n  is the end of the line.  
  Update # 2:  It has been found that the  \ r  characters are coming from a file that is being read and then a filter  After the passage of the output is going to be literally (if (ISIPINT (unsigned char) line [i]) || release ()  issuing  function all  "\ t \ n \ v \ F \ r "gives [ii]) .  
 . You will need to modify this check; You may also block  \ r  and  \ f ; Or alternatively, stop using  issue  and only check  ''   '\ t' , and  Restore your output of \ n " after the loop.

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