Haskell, passing a function to filter in one line? -


I want to filter everything that is not divided by 3 from a list in Hassel, it is technically I What to do 

  Filters (`mod` 3) [1..100]   
 The problem is that, mod x 3 returns a boolean value Will not it be a way of doing it in a row? Or do I need to type another function that gives boolean values? I have read about the CURD Functions, but I am not sure if this is possible because if I used (==) AB and a function, it would not work just.   
 
 
 You can use dot notation  
  filter ( == 0). (`Mod`3)) [1..100]   
 generates it  
  [3,6 9, 12 , 15, 18, 21, 24, 27, 30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87 , 90,93,96,99]   
 Dot type signatures are as follows:  
  (.) :: (b -> c) - & gt; (A -> B) - & gt; A - & gt; C

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