How to store the ASCII value in a character (Ada 83 Only) -


How do I store the ascii value in a character (say 33) I want something like that in Aida 83 No, not 95

c: code 

  char c = 10; char * k = & amp; C; Strncat (des, k, 1); printf ("% s", des);   
 Thanks!   
 
 
  c: letter: = character 'val (10);   
 or  
  C: Character: = ASCIILF;   
 The first work in all the editions of the ADA was the standard method in the second ada 83; It is now the obsolete new way  
  C: character: = ADA. Latin_1.lf; More information: In ADA,  character is a calculator type, not an integer type, therefore, you can not assign an integer to it in the integer  ' Val is a ADA method to convert an integer into a calculation;  Enum_Type'Val (N)  means the Nth calculation defined for "math type, 0-relative". To go to the other side,  Enum_Type'Pos (E)  returns the integer corresponding to the status of the  E  in the list.

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