c++ - I would like to know why my reading of the file is stopping early -


I'm a beginning C ++ user and I have tried to cooperate with my classmates and in this way, but we The answer to this question is that our instructor has given us a linker who runs the main function for us and provides a simple text file for us to read, and for the time being in the second const char * in the title is unimportant , Now for me all Read the data from the file concrete char * saiffile and display it on the screen when I run my program, I have found that it starts reading and I think you will not be able to help because you do not have access to the linker. But any help would be greatly appreciated.

Here's my all code: 

  # include & lt; Iostream & gt; # Include & lt; Fstream & gt; # Include & lt; iomanip & gt; using namespace std; Const int DESC_SIZE = 37; Structure item {int itemId; Description of the character [DESC_SIZE]; Double cost, value; }; Int ProcessIfile (Const four * Safffile, Const char * Raffey) {Fistruff Outfile, Infile; Item inventory; InFile.open (Saiffile, iOS :: In); While (Infile) {inFile & gt; & Gt; Inventory. Item ID & gt; & Gt; Inventory.cast & gt; & Gt; Inventory.price; InFile.getline (Inventory Desscription, DESC_SECE); Cout & lt; & Lt; "" & Lt; & Lt; Inventory. ITMID & lt; & Lt; "" & Lt; & Lt; Setup (5) & lt; & Lt; Inventory.cast & lt; & Lt; "" & Lt; & Lt; Setup (5) & lt; & Lt; Inventory.Print & lt; & Lt; "" & Lt; & Lt; Inventory Description & lt; & Lt; Endl; } Return 0; }    
 
 
 Make sure that the type of data you have received is  inFile < / Code> matches the type that reads  Infile . If not, you will get a stream error and it will stop reading your program.  
 After every read, try  inFile.clear ()  and see if your program is hanging or initially prevents. Alternatively, after each reading Try  
  if (inFile.fail ()) {cout & lt; & Lt; "Read error in file \ n"; }   
 This can not be the answer, but I would like to start debugging here.

Comments

Post a Comment

Popular posts from this blog

Java - Error: no suitable method found for add(int, java.lang.String) -

I'm in the middle of homework work and I'm stuck. At this point in my code, I think that I should have a GUI window that opens and allows me to type "inserted text number". Notice is not going anywhere but at this point, If I pass through the problem then it will be in a linked list. I am getting two of the same error for the lines. Add (index, element); And I can not seem to get past it, there is no suitable method for the error "add (int, java. string string)". Code is below, please advise. To clarify - this will not be a method error because it is a linked list. There should not be any way involved. import java.awt. *; Import java.awt.event. *; Import javax.swing. *; Import java.util. *; Import java.util.Scanner; Import java.util.LinkedList; Public class TopTenList JFrame {Private TopTenList tt; See the Private JTextArea list; Private JTextField cmdTextField; Private JTextField resultsTestfield; // This GUI window is the code for the public toptist...
Read more

java - JPA TypedQuery: Parameter value element did not match expected type -

I am using JPA 2.0 and getting the following code in the DAO layer: Public Zero Test () {string key = "status"; String [] Conditions = {"A", "B"}; & Lt; TestTable & gt; Results = Search (Keys, Conditions); } Public listing & lt; TestTable & gt; Search (string key, object value error) {string sql = "test ndf to testlet and jade nand." + Key + "in:" + key; TypedQuery & LT; TestTable & gt; Query = entityManager.createQuery (SQL, TestTable.class); Query.setParameter (key, Arrays.asList (valueArr)) / *** Error Line *** Return query.getResultList (); } In the above error line, it throws the following exception: java.lang.IllegalArgumentException: parameter value element [[Ljava.lang.String; @ cbe5bc] did not match the expected type [java.lang.String] Why is this expected type string while actually this string []? Please help! Note: This is derived from the normal routine and is a simplified code. I can no...
Read more

c++ - static template member variable has internal linkage but is not defined -

Yes, I know, there is a question with almost the same title, but it refers to a different situation. Error message) In my case, I have a .cpp file with a big named designation name (implementation details). There is a property class template with a static data member in that name space, which I need to access from outside the unknown namespace. I give it a little bit of meat: file.hpp namespace Bar {template & lt; Typename A & gt; Struct foo {static_assert (is_same & lt; a, float & gt; :: value} is_same & lt; a, double>: value, ""); Fixed zero set_static_var (a const & x); // ...}; } and file.cpp namespace {template & lt; Typename A & gt; Struct foo_traits {// supports the implementation of several static code bars: foo & lt; & Gt; Fixed A data; }; The template's & lt; & Gt; Float foo_traits & lt; Float & gt; :: datum; // No change if this is in the global namespace template & lt; & Gt; Doub...
Read more