javascript - check if form is submitted successfully html5 -


मेरे पास कोड है 

  & lt; div class = "form-group" & gt; & lt; लेबल = "store_account_name" & gt; स्टोर शीर्षक & lt; / label & gt; & Lt; input type = "text" value = "" class = "form-control" नाम = "store_account_name" id = "store_account_name" प्लेसहोल्डर = "कृपया बाह्य स्टोर की दुकान का शीर्षक सम्मिलित करें" आवश्यक है & gt; & Lt; / div & gt; & Lt; div वर्ग = "फॉर्म-समूह" & gt; & Lt; label = "store_url" के लिए & gt; स्टोर यूआरएल & lt; / label & gt; & Lt; input type = "url" value = "" class = "form-control" नाम = "store_url" id = "store_url" प्लेसहोल्डर = "कृपया मदद अनुभाग में वर्णित के रूप में स्टोर यूआरएल सम्मिलित करें" आवश्यक / & gt; & Lt; / div & gt;   
 बटन सबमिट करें पर मैं यह जानना चाहता हूं कि फ़ॉर्म मान्य है या नहीं। मेरे पास एक अवरोधक घटना है जो रोकथाम बटन को रोक रहा है। इसलिए मैं केवल एजेक्स कॉल भेजना चाहता हूं, जब इन दोनों इनपुटों को सफलतापूर्वक मान्य किया गया हो। सत्यापन की स्थिति की जांच करने के लिए कोई भी जेएस फ़ंक्शन है या कोई सीएसएस प्रॉपर्टी अमान्य क्षेत्र में जोड़ दी गई है।   
 
 
 आपको फार्म का  ऑनसबमिट  ईवेंट का उपयोग करना चाहिए ऐसा लगता है कि आप सबमिट बटन की क्लिक ईवेंट पर सुन रहे हैं जो सही नहीं है।  
 फ़ॉर्म के मान्य होने पर केवल फ़ॉर्म ही जमा होगा। एचटीएमएलआई सत्यापन नियम इस घटना को फायरिंग से रोका जायेगा यदि यह फ़ॉर्म अमान्य है।  
  
  $ ('# myform')। सबमिट करें (फ़ंक्शन (e) {e। PreventDefault (); // do ajax अब console.log ("सबमिट");});

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