bash - Running script existing in another folder - paths -


मेरे पास तीन स्क्रिप्ट हैं: 

  - bin ------ start Sh - स्क्रिप्ट ------ निर्देशिका_आ ------------ निर्देशिका_ब ------------------ स्क्रिप्ट_1.sh ----- ------------- स्क्रिप्ट_2.sh   
  start.sh  चलाता है  script_1.sh , और फिर  script_1.sh  चलाता है  script_2.sh   
 समस्या पथों के साथ है:  
  start.sh: < / strong>  
  पथ_to_script = "../scripts / directory_a / directory_b / script_1.sh"; कमांड = "$ path_to_script param1 param2"; परिणाम = `$ command`;   
  script_1.sh:   <पूर्व>  path_to_script = "। / Script_2.sh"; कमांड = "$ path_to_script param1 param2"; परिणाम = `$ command`;   
 समस्या यह है कि  script_1.sh  गलत निर्देशिका में  script_2.sh  की तलाश कर रही है:  / bin / script_2 Sh ।  
 मैं इसे इस तरह पूर्ण पथ से गुजारने से ठीक नहीं करना चाहूंगा (क्योंकि 'directory_a' नाम बदल सकता है):  
  script_1.sh:   <पूर्व>  path_to_script = "../ स्क्रिप्ट / निर्देशिका_अ / निर्देशिका_ब / स्क्रिप्ट_2.sh"; कमांड = "$ path_to_script param1 param2"; परिणाम = `$ command`;    
 
 
 सामान्य.श  
 basedir =  < P> पर स्क्रिप्ट start.sh करें:  
  basedir = $ (dirname $ 0) pushd $ basedir absoluteBasedir = $ (पीडब्ल्यूडी) popd export absoluteBasedir स्क्रिप्ट 1 = $ (absolbB) / scripts / directory_a / directory_b /script1.sh   
 स्क्रिप्ट 1:  
  अगर [[-z $ absoluteBasedir]] तो पुशड ../../../ absoluteBasedir = $ (पीडब्ल्यूडी) पॉपड एंड स्क्रिप्ट 2 = $ (पूर्णबैजिर) / स्क्रिप्ट / डायरेक्टरी / ए / डायरेक्टरी / बी / एसक्रिप्ट 2। एसआई   
 सब किया गया है;)

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